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We first construct a LAVF object for E(2),
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And we obtain the fully-integrated LAVF object by solving L,
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As we can see Ls has infinitesimals and constant of integration variables _C1, _C2, _C3. Now let's find the implicit form of Ls,
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Imp is a LHPDE object and has access to various methods.
Ranking of Imp shows that infinitesimals are indeed ranked lower than all other variables.
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We can also fetch the non-integrated determining system of E2 from Ls, by setting option infinitesimalsOnly = true
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The non-integrated determining system S should be same as E2
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