The following is a sketch of a demonstration as to why the limit of a Riemann sum should result in the difference in the endpoint values of an antiderivative of the integrand. The essential link is the Mean Value theorem stated in the form for some between and .
Consider a right Riemann sum for the derivative on the interval . Apply the Mean Value theorem to each subinterval , selecting as the point to evaluate as the for which the equality
holds, . In the Riemann sum, replace each term with so that the Riemann sum becomes
or
which collapses to .
In the limit as and , the need to pick the to satisfy the Mean Value theorem disappears since each subinterval shrinks to zero length, and there must always be an appropriate in every such shrinking subinterval.
In the definite integral (which is just the limit of the Riemann sum) where the integrand is the derivative , the value of the definite integral is the difference , the difference in the endpoint values of the antiderivative.