substance - Maple Help
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Units of Amount of Substance

Description

 • Amount of substance is a base dimension in the International System of Units. The SI unit of amount of substance is the mole, which is defined as an amount of a substance that contains as many elementary entities as there are atoms in 12 grams of carbon-12 (14th CGPM, 1971).
 • When the mole is used, the elementary entities must be specified: atoms, molecules, ions, electrons, other particles, or any specified group of particles. In the Units package, use modifiers and/or attachments in parentheses to indicate the entities.
 • Maple knows the units of amount of substance listed in the following table.

 Name Symbols Context Alternate Spellings Prefixes mole mol SI * moles SI

 An asterisk ( * ) indicates the default context, an at sign (@) indicates an abbreviation, and under the prefixes column, SI indicates that the unit takes all SI prefixes, IEC indicates that the unit takes IEC prefixes, and SI+ and SI- indicate that the unit takes only positive and negative SI prefixes, respectively.  Refer to a unit in the Units package by indexing the name or symbol with the context, for example, mole[SI] or mol[SI]; or, if the context is indicated as the default, by using only the unit name or symbol, for example, mole or mol.
 The unit of amount of substance is defined as follows.
 A mole is defined as approximately $6.0221367×{10}^{23}$ elementary entities.

Examples

 > $\mathrm{convert}\left('\mathrm{mole}','\mathrm{dimensions}','\mathrm{base}'\right)$
 ${\mathrm{amount_of_substance}}$ (1)
 > $\mathrm{convert}\left(337.29,'\mathrm{units}',\frac{'J'}{'\mathrm{mol}\left(\mathrm{carbon12}\right)'},\frac{'\mathrm{kg}'}{'\mathrm{mol}\left(\mathrm{carbon12}\right)'},'\mathrm{energy}'\right)$
 ${3.752857374}{×}{{10}}^{{-15}}$ (2)
 > $\mathrm{convert}\left(337.29,'\mathrm{units}',\frac{'J'}{'\mathrm{mol}\left(\mathrm{carbon12}\right)'},\frac{'\mathrm{kg}'}{'\mathrm{mol}\left(\mathrm{carbon13}\right)'},'\mathrm{energy}'\right)$
 ${3.752857374}{×}{{10}}^{{-15}}$ (3)
 > $\mathrm{convert}\left(337.29,'\mathrm{units}',\frac{'J'}{'\mathrm{mol}\left(\mathrm{carbon12}\right)'},'\mathrm{kg}','\mathrm{energy}','\mathrm{symbolic}'\right)$
 ${6.231766181}{×}{{10}}^{{-39}}$ (4)